How to Do Solution Stoichiometry Using Molarity as a Conversion Factor | How to Pass Chemistry

PRACTICE PROBLEM:
A 34.53 mL sample of H2SO4 reacts with 27.86 mL of 0.08964 M NaOH solution. Calculate the molarity of the H2SO4 solution.

H2SO4 + 2NaOH = Na2SO4 + 2H2O

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STEP BY STEP ANSWER:

Given:
34.53 mL H2SO4
27.86 mL NaOH
0.08964 M NaOH

Find:
M H2SO4

Remember 0.08964 M NaOH means 0.08964 mol NaOH/ 1 L

Step 1: Find mol of H2SO4

Plan: mL NaOH to L NaOH to mol NaOH to mol H2SO4
Metric system molarity NaOH mol to mol ratio
Setup:
27.86 mL NaOH x ( 10^-3 L NaOH/ 1 mL NaOH) x (0.08964 mol NaOH/ 1 L NaOH) x ( 1 mol H2SO4/2 mol NaOH)

= 0.001249 mol H2SO4

Step 2: Convert mL to L of H2SO4

34.53 mL H2SO4 x ( 10^-3 L H2SO4/ 1 mL H2SO4)
= 0.03453 L H2SO4

Step 3: Divide mol/L

M= 0.001249 mol H2SO4/0.03453 L H2SO4

Answer= 0.03617 M H2SO4