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How to find the Oxidation Number for Cl in NaClO2 (Sodium chlorite)

9,274 views July 25, 2020 1:39

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ChannelWayne Breslyn

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To find the correct oxidation state of Cl in NaClO2 (Sodium chlorite), and each element in the compound, we use a few rules and some simple math.

First, since the NaClO2 doesn’t have an overall charge (like NO3- or H3O+) we could say that the total of the oxidation numbers for NaClO2 will be zero since it is a neutral compound.

We write the oxidation number (O.N.) for elements that we know and use these to figure out oxidation number for Cl.

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GENERAL RULES
Free elements have an oxidation state of zero (e.g. Na, Fe, H2, O2, S8).
In an ion the all Oxidation numbers must add up to the charge on the ion.
In a neutral compound all Oxidation Numbers must add up to zero.
Group 1 = +1
Group 2 = +2
Hydrogen with Non-Metals = +1
Hydrogen with Metals (or Boron) = -1
Fluorine = -1
Oxygen = -2 (except in H2O2 or with Fluorine)
Group 17(7A) = -1 except with Oxygen and other halogens lower in the group
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We know that Oxygen usually is -2 with a few exceptions. When Oxygen is in a peroxide, like H2O2 (Hydrogen peroxide), it has a charge of -1. When it is bonded to Fluorine (F) it has an oxidation number of +1.

Here it is bonded to element symbol so the oxidation number on Oxygen is -2. Using this information we can figure out the oxidation number for the element Cl in NaClO2.

About this tutorial

Wayne Breslyn published this 1:39 video tutorial on July 25, 2020. It has been watched 9,274 times on YouTube.

Category
Education
Duration
1:39
Published
July 25, 2020
Views
9,274
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